Finite Math Examples

$h (1) = 12 + 2.4 \sin (\frac{2 π}{365} \cdot (1 - 80))$

Step 1

Replace the variable $1$ with $1$ in the expression.

$h (1) = (1) \cdot 2 + 2.4 \sin (\frac{2 π}{365} \cdot ((1) - 80))$

Step 2

Simplify the result.

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Step 2.1

Simplify each term.

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Step 2.1.1

Multiply $2$ by $1$ .

$h (1) = 2 + 2.4 \sin (\frac{2 π}{365} \cdot ((1) - 80))$

Step 2.1.2

Subtract $80$ from $1$ .

$h (1) = 2 + 2.4 \sin (\frac{2 π}{365} \cdot - 79)$

Step 2.1.3

Multiply $\frac{2 π}{365} \cdot - 79$ .

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Step 2.1.3.1

Combine $\frac{2 π}{365}$ and $- 79$ .

$h (1) = 2 + 2.4 \sin (\frac{2 π \cdot - 79}{365})$

Step 2.1.3.2

Multiply $- 79$ by $2$ .

$h (1) = 2 + 2.4 \sin (\frac{- 158 π}{365})$

Step 2.1.4

Move the negative in front of the fraction.

$h (1) = 2 + 2.4 \sin (- \frac{158 π}{365})$

Step 2.1.5

Add full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$h (1) = 2 + 2.4 \sin (\frac{572 π}{365})$

Step 2.1.6

Evaluate $\sin (\frac{572 π}{365})$ .

$h (1) = 2 + 2.4 \cdot - 0.97784834$

Step 2.1.7

Multiply $2.4$ by $- 0.97784834$ .

$h (1) = 2 - 2.34683601$

Step 2.2

Subtract $2.34683601$ from $2$ .

$h (1) = - 0.34683601$

Step 2.3

The final answer is $- 0.34683601$ .

$- 0.34683601$

Step 3